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प्रश्न
\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]
0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate the volume of chlorine gas formed at S.T.P.
उत्तर
1 mole of chlorine gas has volume = 22.4 dm3
So, 0.02 mole will have volume = 22.4 × 0.02
= 0.448 dm3
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