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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Oxygen Forms Hydrogen Bonding While Chlorine Does Not - Chemistry

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प्रश्न

Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.

उत्तर १

Both chlorine and oxygen have almost the same electronegativity values, but chlorine rarely forms hydrogen bonding. This is because in comparison to chlorine, oxygen has a smaller size and as a result, a higher electron density per unit volume.

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उत्तर २

Both nitrogen (N) and chlorine (Cl) have electronegativity of 3.0. However, only nitrogen is involved in the hydrogen bonds (e.g., NH3) and not chlorine. This is due to smaller atomic size of nitrogen (atomic radius =70 pm) as compared to chlorine (atomic radius = 99) pm), therefore, N can cause greater polarisation of N-H bond than Cl in case of Cl—H bond.Consequently, N atom is involved in hydrogen bonding and not chlorine.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: The p-block Elements - Exercises [पृष्ठ २०७]

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एनसीईआरटी Chemistry [English] Class 12
पाठ 7 The p-block Elements
Exercises | Q 25 | पृष्ठ २०७

संबंधित प्रश्‍न

Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


Give reasons for the following : Oxygen has less electron gain enthalpy with negative sign than sulphur.


Write the order of thermal stability of the hydrides of Group 16 elements.


Which of the following does not react with oxygen directly?

Zn, Ti, Pt, Fe


Knowing the electron gain enthalpy values for O → O and O → O2− as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O? (Hint: Consider lattice energy factor in the formation of compounds).


Draw the structures of `H_3PO_2`

 


Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy


The formation of \[\ce{O^+_2[PtF6]^-}\] is the basis for the formation of first xenon compound. This is because ____________.


Match the items of Columns I and II and mark the correct option.

Column I Column II
(A) \[\ce{H2SO4}\] (1) Highest electron gain enthalpy
(B) \[\ce{CCl3NO2}\] (2) Chalcogen
(C) \[\ce{Cl2}\] (3) Tear gas
(D) Sulphur (4) Storage batteries

Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]


Write a balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen.


Which of the following compound is a peroxide?


These are physical properties of an elements.

  1. Sublimation enthalpy
  2. Ionisation enthalpy
  3. Hydration enthalpy
  4. Electron gain enthalpy

The total number of above properties that affect the reduction potential is ______. (Integer answer)


What is the basicity of \[\ce{H3PO4}\]?


______ is a gaseous element of group 16.


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