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P the Time Period of a Particle in Simple Harmonic Motion is Equal to the Smallest Time Between the Particle Acquiring a Particular Velocity → V . - Physics

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प्रश्न

The time period of a particle in simple harmonic motion is equal to the smallest time between the particle acquiring a particular velocity \[\vec{v}\] . The value of v is

पर्याय

  • vmax

  • 0

  • between 0 and vmax

  • between 0 and −vmax

MCQ

उत्तर

vmax

Because the time period of a simple harmonic motion is defined as the time taken to complete one oscillation.

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पाठ 12: Simple Harmonics Motion - MCQ [पृष्ठ २५०]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 12 Simple Harmonics Motion
MCQ | Q 3 | पृष्ठ २५०

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

A particle executes S.H.M. with a period of 10 seconds. Find the time in which its potential energy will be half of its total energy.


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It is proposed to move a particle in simple harmonic motion on a rough horizontal surface by applying an external force along the line of motion. Sketch the graph of the applied force against the position of the particle. Note that the applied force has two values for a given position depending on whether the particle is moving in positive or negative direction.


Can the potential energy in a simple harmonic motion be negative? Will it be so if we choose zero potential energy at some point other than the mean position?


The motion of a torsional pendulum is
(a) periodic
(b) oscillatory
(c) simple harmonic
(d) angular simple harmonic


A particle moves on the X-axis according to the equation x = x0 sin2 ωt. The motion is simple harmonic


Which of the following will change the time period as they are taken to moon?
(a) A simple pendulum
(b) A physical pendulum
(c) A torsional pendulum
(d) A spring-mass system


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A particle is subjected to two simple harmonic motions, one along the X-axis and the other on a line making an angle of 45° with the X-axis. The two motions are given by x = x0 sin ωt and s = s0 sin ωt. Find the amplitude of the resultant motion.


In a simple harmonic oscillation, the acceleration against displacement for one complete oscillation will be __________.


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Define the time period of simple harmonic motion.


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A spring is stretched by 5 cm by a force of 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is ______.


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Displacement vs. time curve for a particle executing S.H.M. is shown in figure. Choose the correct statements.

  1. Phase of the oscillator is same at t = 0 s and t = 2s.
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  3. Phase of the oscillator is same at t = 1 s and t = 7s.
  4. Phase of the oscillator is same at t = 1 s and t = 5s.

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