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P the Time Period of a Particle in Simple Harmonic Motion is Equal to the Smallest Time Between the Particle Acquiring a Particular Velocity → V . - Physics

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प्रश्न

The time period of a particle in simple harmonic motion is equal to the smallest time between the particle acquiring a particular velocity \[\vec{v}\] . The value of v is

विकल्प

  • vmax

  • 0

  • between 0 and vmax

  • between 0 and −vmax

MCQ

उत्तर

vmax

Because the time period of a simple harmonic motion is defined as the time taken to complete one oscillation.

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अध्याय 12: Simple Harmonics Motion - MCQ [पृष्ठ २५०]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 12 Simple Harmonics Motion
MCQ | Q 3 | पृष्ठ २५०

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

The average displacement over a period of S.H.M. is ______.

(A = amplitude of S.H.M.)


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(a) simple harmonic
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(b) the minimum potential energy equals the minimum kinetic energy
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(a) A simple pendulum
(b) A physical pendulum
(c) A torsional pendulum
(d) A spring-mass system


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A particle is subjected to two simple harmonic motions, one along the X-axis and the other on a line making an angle of 45° with the X-axis. The two motions are given by x = x0 sin ωt and s = s0 sin ωt. Find the amplitude of the resultant motion.


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Which of the following expressions corresponds to simple harmonic motion along a straight line, where x is the displacement and a, b, and c are positive constants?


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