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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Ratio of corresponding sides of two similar triangles is 4:7, then find the ratio of their areas = ? - Geometry Mathematics 2

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प्रश्न

Ratio of corresponding sides of two similar triangles is 4:7, then find the ratio of their areas = ?

बेरीज

उत्तर

Let the corresponding sides of similar triangles be s1 and s2.

Let A1 and A2 be their corresponding areas.

s1 : s2 = 4 : 7        ......[Given]

∴ `"s"_1/"s"_2= 4/7`     ......(i)

by theorem of areas of similar triangles,

`"A"_1/"A"_2 = "s"_1^2/"s"_2^2`  

`"A"_1/"A"_2 = ("s"_1/"s"_2)^2`

`"A"_1/"A"_2 = (4/7)^2`    ......[From (i)]

`"A"_1/"A"_2 = 16/49`

∴ Ratio of areas of similar triangles = 16 : 49

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पाठ 1: Similarity - Q.1 (B)

संबंधित प्रश्‍न

In the following figure seg AB ⊥ seg BC, seg DC ⊥ seg BC. If AB = 2 and DC = 3, find `(A(triangleABC))/(A(triangleDCB))`


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\[\frac{BD}{CD} = \frac{AB}{AC}\]

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find `("A"(∆"ABC"))/("A"(∆"ADB"))`


In adjoining figure, PQ ⊥ BC, AD ⊥ BC then find following ratios.

  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
  4. `("A"(∆"ADC"))/("A"(∆"PQC"))`

 In trapezium PQRS, side PQ || side SR, AR = 5AP, AS = 5AQ then prove that, SR = 5PQ 

 

 


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`"A(∆ ABD)"/"A(∆ ADC)"`


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In the figure, PM = 10 cm, A(∆PQS) = 100 sq.cm, A(∆QRS) = 110 sq. cm, then find NR.


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`(A(∆ABD))/(A(∆ABC))`


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\[\frac{A\left( ∆ ADC \right)}{A\left( ∆ ABC \right)}\] 


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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.


Given: PQ ⊥ BC, AD ⊥ BC

Now, A(ΔPQB)  = `1/2 xx square xx square`

A(ΔPBC)  = `1/2 xx square xx square`

Therefore, 

`(A(ΔPQB))/(A(ΔPBC)) = (1/2 xx square xx square)/(1/2 xx square xx square)`

= `square/square`


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