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Show that there is a root for the equation 2x3 − x − 16 = 0 between 2 and 3. - Mathematics and Statistics

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प्रश्न

Show that there is a root for the equation 2x3 − x − 16 = 0 between 2 and 3.

बेरीज

उत्तर

Let f(x) = 2x3 − x − 16 

f(x) is a polynomial function and hence it is continuous for all x ∈ R

A root of f(x) exists if f(x) = 0 for at least one value of x

f(2) = 2(2)3 – 2 – 16

= – 2 < 0

f(3) = 2(3)3 – 3 – 16

= 35 > 0

∴ f(2) < 0 and f(3) > 0

∴ By intermediate value theorem, there has to be point ‘c’ between 2 and 3 such that f(c) = 0

∴ There is a root of the given equation between 2 and 3.

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Continuous and Discontinuous Functions
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Continuity - EXERCISE 8.1 [पृष्ठ १७५]

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