Advertisements
Advertisements
प्रश्न
Simplify :
`( 8x^3 ÷ 125y^3 )^(2/3)`
उत्तर
`( 8x^3 ÷ 125y^3 )^(2/3)`
= `([ 2x xx 2x xx 2x ]/[5y xx 5y xx 5y ])^(2/3)`
= `[((2x)/(5y))^3]^(2/3)`
= `((2x)/(5y))^( 3 xx 2/3 )`
= `((2x)/(5y))^2`
= `[ (2x)/(5y) xx (2x)/(5y) ]`
= `[4x^2]/[25y^2]`
APPEARS IN
संबंधित प्रश्न
Evaluate :
`3^3 xx ( 243 )^(-2/3) xx 9^(-1/3)`
Evaluate :
`(16/81 )^(-3/4) xx (49/9)^(3/2) ÷ (343/216)^(2/3)`
Simplify :
`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`
Simplify :
`( 3x^2 )^(-3) xx ( x^9 )^(2/3)`
Simplify the following and express with positive index :
`(3^-4/2^-8)^(1/4)`
If 1960 = 2a. 5b. 7c, calculate the value of 2-a. 7b. 5-c.
Simplify :
`[ 8^3a xx 2^5 xx 2^(2a) ]/[ 4 xx 2^(11a) xx 2^(-2a) ]`
Simplify :
`( x^a/x^b)^( a^2 + ab + b^2 ) xx (x^b/x^c)^(b^2 + bc + c^2) xx (x^c/x^a)^( c^2 + ca + a^2 )`
Simplify:
`( x^a/x^-b )^( a^2 - ab + b^2 ) xx ( x^b/x^-c )^( b^2 - bc + c^2 ) xx ( x^c/x^-a )^( c^2 - ca + a^2 )`
Evaluate the following: `(3^2)^2`