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प्रश्न
Solve` 2x^2+ax-a^2=0`
उत्तर
`2x^2+ax-a^2=0`
⇒`2x^2+2ax-ax-a^2`
⇒`2x(x+a)-a(x+a)=0`
⇒`(x+a)(2x-a)=0`
⇒`x+a=0 or 2x-a=0`
⇒`x=-a or x=a/2`
Hence, `a and a/2` are the roots of the given equation.
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