Advertisements
Advertisements
प्रश्न
If the roots of the equation` ax^2+bx+c=0` are equal then c=?
(a)`b/(2a)` (b) `b/(2a)` (c) `-b^2/(4a)` (d) `B^2/(4a)`
उत्तर
(d) `b^2/(4a)`
It is given that the roots of the equation `(ax^2+bx+c=0)`are equal.
∴`(b^2-4ac)=0`
⇒`b^2=4ac`
⇒ `c=b^2/(4a)`
APPEARS IN
संबंधित प्रश्न
The roots of a quadratic equation are 5 and -2. Then, the equation is
(a)`x^2-3x+10=0` (b)`x^2-3x-10=0` (c)x^2+3x-10=0 (d)`x^2+3x+10=0`
The sum of a number and its reciprocal is `2 1/20` The number is
(a) `5/4 or 4/5` (b)`4/3 or 3/4`
(c) `5/6 or 6/5` (d) `1/6 or 6`
If the quadratic equation `px^2-2sqrt5px+15=0` has two equal roots then find the value of p.
Decide whether the following equation is quadratic equation or not.
\[x + \frac{1}{x} = - 2\]
Ranjana wants to distribute 540 oranges among some students. If 30 students were more each would get 3 oranges less. Find the number of students.
If 3x + 5y = 9 and 5x + 3y = 7 find the value of x + y.
Solve for x : `1/(2a + b + 2x) =1/(2a) + 1/b + 1/(2x); x ≠ 0, x ≠ (−2a −b)/2`, a, b ≠ 0
Mukund has ₹ 50 more than Sagar. If the product of the amount they have is 15,000, then find the amount each has
The ratio of fruit trees and vegetable trees in an orchard is 3:4. If 6 more trees of each type are planted, the ratio of trees would be 6:7. Find the number of fruit trees and vegetable trees in the orchard.
The ratio of fruit trees and vegetable trees = 3:4
So, let the number of fruit trees= 3x and the number of vegetable trees = `square`
From the given condition,
`(3x + square)/(square + square) = square/square`
`square (3x + square) = square (square + square)`
`square + square = square + square`
`square - square = square - square`
`- square = - square`
`square = square`
x = `square`
∴ Number of fruit trees in the orchard = 3x = 3 × `square` = `square` and number of vegetable trees in the orchard = 4x = 4 × `square` = `square`
Hence, the number of fruit trees and vegetable trees in the orchard are `square` and `square` respectively.
In a right-angled triangle, altitude is 2 cm longer than its base. Find the dimensions of the right-angled triangle given that the length of its hypotenuse is 10 cm.
