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Solve 3x + 8 > 2, when x is a real number. - Mathematics

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प्रश्न

Solve 3x + 8 > 2, when x is a real number.

बेरीज

उत्तर

The given inequality is 3x + 8 > 2.

3x + 8 > 2

⇒ 3x + 8 - 8 > 2 - 8

⇒ 3x > - 6

⇒ `(3x)/3 > (-6)/3`

⇒ x > - 2

When x is a real number, the solutions of the given inequality are all the real numbers, which are greater than –2.

Thus, in this case, the solution set is (– 2, ∞).

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पाठ 6: Linear Inequalities - Exercise 6.1 [पृष्ठ १२२]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 6 Linear Inequalities
Exercise 6.1 | Q 4.2 | पृष्ठ १२२

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