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प्रश्न
Solve the following pair of linear equations.
(a − b) x + (a + b) y = a2− 2ab − b2
(a + b) (x + y) = a2 + b2
उत्तर
(a − b) x + (a + b) y = a2− 2ab − b2 … (1)
(a + b) (x + y) = a2 + b2
(a + b) x + (a + b) y = a2 + b2 … (2)
Subtracting equation (2) from (1), we obtain
(a − b) x − (a + b) x = (a2 − 2ab − b2) − (a2 + b2)
(a − b − a − b) x = − 2ab − 2b2
− 2bx = − 2b (a + b)
x = a + b
Using equation (1), we obtain
(a − b) (a + b) + (a + b) y = a2 − 2ab − b2
a2 − b2 + (a + b) y = a2− 2ab − b2
(a + b) y = − 2ab
`y = (-2ab)/(a+b)`
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