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प्रश्न
Solve the following differential equation:
`(ydx - xdy) cot (x/y)` = ny2 dx
उत्तर
`(ydx - xdy) cot (x/y)` = ny2 dx
Dividing throughout by 'y2'
`((ydx - xdy)/y^2) cot (x/y)` = n dx
`"d"(x/y)* cot(x/y)` = n dx
`int cot(x/y)* "d"(x/y) = "n" int "d"x`
`log sin(x/y)` = nx + c
`sin(x/y) = "e"^("n"x + "c")`
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