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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Solve: xxxx-15-x3=1-x-202 - Mathematics

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प्रश्न

Solve: `("x" - 1)/5 - "x"/3 = 1 - ("x" - 2)/2`

बेरीज

उत्तर

`("x" - 1)/5 - "x"/3 = 1 - ("x" - 2)/2`

⇒ `(6"x" - 6 - 10"x" = 30 - 15"x" + 30)/30`

⇒ − 4x − 6 = 60 − 15x

⇒ 15x − 4x = 60 + 6

⇒ 11x = 66

⇒ x = `66/11`

∴ x = 6

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Simple Linear Equations in One Variable
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पाठ 12: Simple Linear Equations (Including Word Problems) - Exercise 12 (C)

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सेलिना Concise Mathematics [English] Class 7 ICSE
पाठ 12 Simple Linear Equations (Including Word Problems)
Exercise 12 (C) | Q 29
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