Advertisements
Advertisements
प्रश्न
The coordination number of atoms in body-centred cubic structure (bcc) is ______.
पर्याय
4
6
8
12
उत्तर
The coordination number of atoms in body-centred cubic structure (bcc) is 8.
Explanation:
In body-centered cubic structure, atoms occupy all the corners of the cube and body centre position in a unit cell.
∴ Coordination number of atoms in BCC structure = 8
APPEARS IN
संबंधित प्रश्न
Answer the following in brief.
Calculate the number of atoms in fcc unit cell.
An element with molar mass 27 g/mol forms a cubic unit cell with edge length of 405 pm. If the density of the element is 2.7 g/cm3, what is the nature of the cubic unit cell?
Give the percentage of empty space in bcc lattice.
If the total volume of a simple cubic unit cell is 6.817 × 10-23 cm3, what is the volume occupied by particles in the unit cell?
Calculate the number of unit cells in 0.3 g of a species having density of 8.5 g/cm3 and unit cell edge length 3.25 × 10-8 cm.
Silver crystallises in fcc structure, if edge length of unit cell is 316.5 pm. What is the radius of silver atom?
An element crystallizes in fcc type of unit cell. The volume of one unit cell is 24.99 × 10-24 cm3 and density of the element 7.2 g cm-3, Calculate the number of unit cells in 36 g of pure sample of element?
What is the percentage of unoccupied space in fcc unit cell?
In bcc unit cell, the edge length (a) and radius of sphere (r) are related to each other by equation:
An element (atomic mass M g/mol) having bcc structure has unit cell edge 400 pm. The density of the element is ____________ g/cm3.
[NA = 6.0 × 1023 atom mol−1)
How many total constituent particles are present in simple cubic unit cell?
The number of atoms in 500 g of a fcc crystal of a metal with density d = 10 g/cm3 and cell edge 100 pm, is equal to ____________.
Sodium crystallizes in bcc structure with radius 1.86 × 10−8 cm. What is the length of unit cell of sodium?
Copper and silver have ____________ crystal structure.
Consider the following unit cell.
The number of particles (spheres) per unit cell is:
Which of the following formulae is used to find edge length of bee unit cell?
The number of atoms in 100 g of an fcc crystal with density 10 g cm-3 and unit cell edge length 200 pm is equal to ______.
Gold crystallises into face-centred cubic cells. The edge length of a unit cell is 4.08 × 10–8 cm. Calculate the density of gold. [Molar mass of gold = 197 g mol–1]
A metal has an fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm−3. The molar mass of the metal is ______.
(NA Avogadro's constant = 6.02 × 1023 mol−1)
Identify unit cell from following having four particles in it
An element with molar mass 2.7 × 10-2 kg/mol. Forms a cubic units cell with edge length of 405 pm. If the density is 2.7 × 103 kg/m3. Find the nature of a cubic unit cell.
The correct sequence of the atomic layers in cubic close packing is ______.
What would be the empirical formula of a compound having a unit cell containing A ion shared equally at the corner of the cube and B ion on the centre of faces of the cube?
An element crystallises in fee structure. If molar mass of element is 72.7 g mol -1, the mass of its one unit cell will be ______.
The number of particles present in Face Centred Cubic Unit cell is/are ______.
