मराठी

The frequency distribution has been represented graphically as follows: Marks 0 – 20 20 – 40 40 – 60 60 – 100 Number of Students 10 15 20 25 Do you think this representation is correct? Why? - Mathematics

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प्रश्न

The frequency distribution has been represented graphically as follows:

Marks 0 – 20  20 – 40 40 – 60 60 – 100
Number of Students 10 15 20 25


Do you think this representation is correct? Why?

आलेख

उत्तर

No, here the widths of the rectangles are varying, so we need to make certain modifications in the length of the rectangles so that the areas are proportional to the frequencies.

We proceed as follows:

1. Select a class interval with the minimum class size, here the minimum class size is 20.

2. The length of the rectangles are then modified to be proportionate to the class size 20.

Now, we get the following modified table:

Marks Number of students
(Frequency)
Width of the
class
Length of the
rectangle
0 – 20 10 20 `10/20 xx 20 = 10`
20 – 40 15 20 `15/20 xx 20 = 15`
40 – 60 20 20 `20/20 xx 20 = 20`
60 – 100 25 40 `25/40 xx 20 = 12.5`

So, the correct histogram with varying width is given below:

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पाठ 14: Statistics & Probability - Exercise 14.2 [पृष्ठ १३६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
पाठ 14 Statistics & Probability
Exercise 14.2 | Q 1. | पृष्ठ १३६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The length of 40 leaves of a plant are measured correct to one millimetre, and the obtained data is represented in the following table:-

Length (in mm) Number of leaves
118 - 126 3
127 - 135 5
136 - 144 9
145 - 153 12
154 - 162 5
163 - 171 4
172 - 180
  1. Draw a histogram to represent the given data. [Hint: First make the class intervals continuous]
  2. Is there any other suitable graphical representation for the same data?
  3. Is it correct to conclude that the maximum number of leaves are 153 mm long? Why?

The runs scored by two teams A and B on the first 60 balls in a cricket match are given below:

Number of balls Team A Team B
1 - 6 2 5
7 - 12 1 6
13 - 18 8 2
19 - 24 9 10
25 - 30 4 5
31 - 36 5 6
37 - 42 6 3
43 - 48 10 4
49 - 54 6 8
55 - 60 2 10

Represent the data of both the teams on the same graph by frequency polygons.

[Hint: First make the class intervals continuous.]


The following table gives the route length (in thousand kilometres) of the Indian Railways in some of the years:

Year 1960-61 1970-71 1980-81 1990-91 2000-2001
Route length
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56 60 61 74 98

Represent the above data with the help of a bar graph.


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Construct a bar graph to represent the above data.


A frequency polygon is constructed by plotting frequency of the class interval and the


In the 'less than' type of ogive the cumulative frequency is plotted against


Draw frequency polygons for each of the following frequency distribution: 

(a) using histogram

(b) without using histogram

C.I

10 - 30

30 - 50

50 - 70 70 - 90 90 - 110 110 - 130 130 - 150
ƒ  4 7 5 9 5 6 4

Construct a frequency polygon for the following distribution:

Class-intervals 0-4 4 - 8 8 - 12 12 - 16 16 - 20 20 - 24
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Construct a combined histogram and frequency polygon for the following frequency distribution:

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The daily wages in a factory are distributed as follows:

Daily wages (in Rs.)

125 - 175

175 - 225

225 - 275

275 - 325

325 - 375

Number of workers

4

20

22

10

6

Draw a frequency polygon for this distribution.


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