Advertisements
Advertisements
प्रश्न
The line given by the equation `2x - y/3 = 7` passes through the point (k, 6); calculate the value of k.
उत्तर
Given, the line given by the equation `2x - y/3 = 7` passes through the point (k, 6).
Substituting x = k and y = 6 in the given equation, we have:
`2x - 6/3 = 7`
2k – 2 = 7
2k = 9
k = `9/2`
k = 4.5
APPEARS IN
संबंधित प्रश्न
State, true or false :
The line `x/2 + y/3 = 0` passes through the point (4, −6).
The line x – 6y + 11 = 0 bisects the join of (8, −1) and (0, k). Find the value of k.
Find the equation of a line whose : y-intercept = −1 and inclination = 45°
Find the equation of the perpendicular dropped from the point (−1, 2) onto the line joining the points (1, 4) and (2, 3).
Find the equation of the line passing through the point of intersection of 7x + 6y = 71 and 5x – 8y = −23; and perpendicular to the line 4x – 2y = 1.
Find the equation of a line passing through the point (2, 3) and having the x-intercept of 4 units.
Find if the following points lie on the given line or not:
(2,4) on the line y = 2x - 1
The line y = 6- `(3"x")/2` passes through the point (r,3). Find the value of r.
The coordinates of two points P and Q are (0,4) and (3,7) respectively. Find
(i) The gradient of PQ
(ii) the equation of PQ
(iii) the coordinates of the point where the line AB intersects the X-axis.
Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.
