Advertisements
Advertisements
Question
The line given by the equation `2x - y/3 = 7` passes through the point (k, 6); calculate the value of k.
Solution
Given, the line given by the equation `2x - y/3 = 7` passes through the point (k, 6).
Substituting x = k and y = 6 in the given equation, we have:
`2x - 6/3 = 7`
2k – 2 = 7
2k = 9
k = `9/2`
k = 4.5
APPEARS IN
RELATED QUESTIONS
A line AB meets X – axis at A and Y –axis at B. P (4, -1) divides AB in the ratio 1 : 2.
1) Find the coordinates of A and B.
2) Find the equation of the line through P and perpendicular to AB.
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(0, 5)
The line `(3x)/5 - (2y)/3 + 1 = 0` contains the point (m, 2m – 1); calculate the value of m.
A(1, 4), B(3, 2) and C(7, 5) are vertices of a triangle ABC. Find the co-ordinates of the centroid of triangle ABC.
A(7, −1), B(4, 1) and C(−3, 4) are the vertices of a triangle ABC. Find the equation of a line through the vertex B and the point P in AC; such that AP : CP = 2 : 3.
The line segment joining the points A(3, −4) and B(−2, 1) is divided in the ratio 1 : 3 at point P in it. Find the co-ordinates of P. Also, find the equation of the line through P and perpendicular to the line 5x – 3y = 4.
The line 2x - 5y + 31 = 0 bisects the join of (-4,5) and (P, 9). Find the value of p.
Find the equation of a line passing through (8,3) and making an angle of 45° with the positive direction of the y-axis.
Find the value of a for which the points A(a, 3), B(2, 1) and C(5, a) are collinear. Hence, find the equation of the line.
Find the equation of a line that has Y-intercept 3 units and is perpendicular to the line joining (2, – 3) and (4, 2).