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प्रश्न
The maximum velocity of a particle performing linear S.H.M. is 0.16 m/s. If its maximum acceleration is 0.64 m/s2, calculate its period.
उत्तर
vmax = 0.16 m/s, amax =0.64 m/s2
Period (T) = ?
vmax = Aω and amax = Aω2
`a_max/v_max=omega=(2pi)/T`
`T=(2pixxv_max)/a_max`
`=(2xx3.14xx0.16)/0.64`
`= 1.571 s`
Period of particle is 1.571 s
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