मराठी

The Mid-point of the Line Segment Joining a (- 2 , 0) and B (X , Y) is P (6 , 3). Find the Coordinates of B. - Mathematics

Advertisements
Advertisements

प्रश्न

The mid-point of the line segment joining A (- 2 , 0) and B (x , y) is P (6 , 3). Find the coordinates of B.

बेरीज

उत्तर

Coordinates of P are ,

P (6 , 3) = P `((-2 + "x")/2 , (0 + "y")/2)`

`6 = (- 2 + "x")/2 , 3 = "y"/2`

⇒ 12 = - 2 + x , y = 6

⇒ x = 14

Coordinates of B are (14 , 6)

shaalaa.com
The Mid-point of a Line Segment (Mid-point Formula)
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Distance and Section Formulae - Exercise 12.3

APPEARS IN

फ्रँक Mathematics - Part 2 [English] Class 10 ICSE
पाठ 12 Distance and Section Formulae
Exercise 12.3 | Q 12

संबंधित प्रश्‍न

Points A and B have co-ordinates (3, 5) and (x, y) respectively. The mid-point of AB is (2, 3). Find the values of x and y.


(–5, 2), (3, −6) and (7, 4) are the vertices of a triangle. Find the length of its median through the vertex (3, −6).


Find the coordinates of point P if P divides the line segment joining the points A(–1, 7) and B(4, –3) in the ratio 2 : 3.


Find the coordinates of the midpoint of the line segment joining P(0, 6) and Q(12, 20).


The points (2, -1), (-1, 4) and (-2, 2) are midpoints of the sides ofa triangle. Find its vertices.


Find the centroid of a triangle whose vertices are (3, -5), (-7, 4) and ( 10, -2).


A triangle is formed by line segments joining the points (5, 1 ), (3, 4) and (1, 1). Find the coordinates of the centroid.


O(0, 0) is the centre of a circle whose one chord is AB, where the points A and B are (8, 6) and (10, 0) respectively. OD is the perpendicular from the centre to the chord AB. Find the coordinates of the mid-point of OD.


If the coordinates of one end of a diameter of a circle is (3, 4) and the coordinates of its centre is (−3, 2), then the coordinate of the other end of the diameter is


Point P is the centre of the circle and AB is a diameter. Find the coordinates of points B if coordinates of point A and P are (2, – 3) and (– 2, 0) respectively.


Given: A`square` and P`square`. Let B (x, y)

The centre of the circle is the midpoint of the diameter.

∴ Mid point formula,

`square = (square + x)/square`

⇒ `square = square` + x

⇒ x = `square - square`

⇒ x = – 6

and `square = (square + y)/2`

⇒ `square` + y = 0

⇒ y = 3

Hence coordinates of B is (– 6, 3).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×