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प्रश्न
The percentage marks obtained in 10 subjects by a student are 84, 88, 72, 91, 68, 75, 98, 96, 79 and 86. Find the median of the marks obtained.
उत्तर
Arranging the given data in descending order :
98, 96, 91, 88, 86, 84, 79, 75, 72, 68
The middle term are 86 and 84 which are 5th and 6th terms
median = `(86 + 84 )/2 = 170/2 = 85`
Therefore, Median of marks = 85.
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संबंधित प्रश्न
Using step-deviation method, calculate the mean marks of the following distribution.
| C.I. | 50 – 55 | 55 – 60 | 60 – 65 | 65 – 70 | 70 – 75 | 75 – 80 | 80 – 85 | 85 – 90 |
| Frequency | 5 | 20 | 10 | 10 | 9 | 6 | 12 | 8 |
Find the mean, median and mode of the following marks obtained by 16 students in a class test marked out of 10 marks:
0, 0, 2, 2, 3, 3, 3, 4, 5, 5, 5, 5, 6, 6, 7 and 8.
The following table given the weekly of workers in a factory:
| Weekly wages (in Rs) | No.of workers |
| 50-55 | 5 |
| 55-60 | 20 |
| 60-65 | 10 |
| 65-70 | 10 |
| 70-75 | 9 |
| 75-80 | 6 |
| 80-85 | 12 |
| 85-90 | 8 |
Calcculate: (1)the mean, (2) the model class, (3) th number of workers getting weekly qages below Rs. 80 and (4) the number of workers getting Rs. 65 or more but less than Rs.85 as weekly wages.
Find the mean (correct to one place of decimal) by using short-cut method.
|
x |
40 |
41 |
43 |
45 |
46 |
49 |
50 |
|
f |
14 |
28 |
38 |
50 |
40 |
20 |
10 |
Find the median of:
63, 17, 50, 9, 25, 43, 21, 50, 14 and 34
The mean of 18, 28, x, 32, 14 and 36 is 23. Find the value of x. Sum of data
Find the median of 26, 33, 41, 18, 30, 22, 36, 45 and 24
Find the mean and the median of: 10,12, 12, 15, 15, 17, 18, 18, 18 and 19
The median of observation 11, 12, 14, 18, x + 2, x + 4, 30, 32, 35, 41 arranged in ascending order is 24. Find the values of x
The median of any data lies between the ______ and ______ observations.
