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प्रश्न
The percentage marks obtained in 10 subjects by a student are 84, 88, 72, 91, 68, 75, 98, 96, 79 and 86. Find the median of the marks obtained.
उत्तर
Arranging the given data in descending order :
98, 96, 91, 88, 86, 84, 79, 75, 72, 68
The middle term are 86 and 84 which are 5th and 6th terms
median = `(86 + 84 )/2 = 170/2 = 85`
Therefore, Median of marks = 85.
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संबंधित प्रश्न
The mean of the following distribution is 52 and the frequency of class interval 30-40 is ‘f’. Find ‘f’.
| Class Interval | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
| Frequency | 5 | 3 | f | 7 | 2 | 6 | 13 |
If 69.5 is the mean of 72, 70, ‘x’, 62, 50, 71, 90, 64, 58 and 82, find the value of ‘x’.
Using a graph paper, draw an ogive for the following distribution which shows a record of the width in kilograms of 200 students.
| Weight | Frequency |
| 40 – 45 | 5 |
| 45 – 50 | 17 |
| 50 – 55 | 22 |
| 55 – 60 | 45 |
| 60 – 65 | 51 |
| 65 – 70 | 31 |
| 70 – 75 | 20 |
| 75 – 80 | 9 |
Use your ogive to estimate the following:
- The percentage of student weighting 55 kg or more
- The weight above which the heaviest 30% of the student fall
- The number of students who are
- underweight
- overweight, If 55.70 kg is considered as standard weight.
If the mean of 8 , 14 , 20 , x and 12 is 13, find x.
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| Pocket money per week in Rs | 25 | 50 | 75 | 100 | 125 | 150 |
| No. of students | 4 | 7 | 13 | 18 | 6 | 2 |
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| I.Q. Score | 80-100 | 100-120 | 120-140 | 140-160 | 160-180 | 180-200 |
| No. of Students | 6 | 9 | 16 | 13 | 4 | 2 |
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
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| No. of boys | 10 | 12 | 14 | 12 | 9 | 7 | 6 |
The following data have been arranged in ascending order. If their median is 63, find the value of x.
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128, 144, 146, 143, 136, 142, 138, 129, 140, 152, 144, 140, 150, 142, 154
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