Advertisements
Advertisements
प्रश्न
The perimeter of the rectangle whose length is 60 cm and a diagonal is 61 cm is ______.
पर्याय
120 cm
122 cm
71 cm
142 cm
उत्तर
The perimeter of the rectangle whose length is 60 cm and a diagonal is 61 cm is 142 cm.
Explanation:
Consider the rectangle PQRS,
Given, length of rectangle PQ = 60 cm, Diagonal of the rectangle = 61 cm.
To find out the height of the rectangle, consider the right angled triangle PQR.
From the Pythagoras theorem, PR2 = PQ2 + RQ2
⇒ 612 = 602 + RQ2
⇒ 3721 = 3600 + RQ2
⇒ RQ2 = 3721 – 3600
⇒ RQ2 = 121
⇒ RQ = `sqrt(121)`
⇒ RQ = 11 cm
Then, the perimeter of the rectangle PQRS = 2(Length + Breadth)
= 2(60 + 11)
= 2(71)
= 142 cm
APPEARS IN
संबंधित प्रश्न
Tick the correct answer and justify: In ΔABC, AB = `6sqrt3` cm, AC = 12 cm and BC = 6 cm.
The angle B is:
In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that:
`"AC"^2 = "AD"^2 + "BC"."DM" + (("BC")/2)^2`
In the given figure, M is the midpoint of QR. ∠PRQ = 90°. Prove that, PQ2 = 4PM2 – 3PR2.
Diagonals of rhombus ABCD intersect each other at point O.
Prove that: OA2 + OC2 = 2AD2 - `"BD"^2/2`
M andN are the mid-points of the sides QR and PQ respectively of a PQR, right-angled at Q.
Prove that:
(i) PM2 + RN2 = 5 MN2
(ii) 4 PM2 = 4 PQ2 + QR2
(iii) 4 RN2 = PQ2 + 4 QR2(iv) 4 (PM2 + RN2) = 5 PR2
In the given figure, AD = 13 cm, BC = 12 cm, AB = 3 cm and angle ACD = angle ABC = 90°. Find the length of DC.
If ‘l‘ and ‘m’ are the legs and ‘n’ is the hypotenuse of a right angled triangle then, l2 = ________
In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?
In the adjoining figure, a tangent is drawn to a circle of radius 4 cm and centre C, at the point S. Find the length of the tangent ST, if CT = 10 cm.
If the areas of two circles are the same, they are congruent.