Advertisements
Advertisements
प्रश्न
The product of the digits of a two digit number is 24. If its unit’s digit exceeds twice its ten’s digit by 2; find the number.
उत्तर
Let the ten’s and unit’s digit of the required number be x and y respectively.
From the given information,
x × y = 24
y = `24/x` ...(1)
Also, y = 2x + 2
`24/x = 2x + 2` ...[Using (1)]
24 = 2x2 + 2x
2x2 + 2x – 24 = 0
x2 + x – 12 = 0
(x + 4)(x – 3) = 0
x = – 4, 3
The digit of a number cannot be negative, so x = 3
∴ y = `24/3` = 8
Thus, the required number is 38.
APPEARS IN
संबंधित प्रश्न
The sum of the squares of two consecutive natural numbers is 41. Find the numbers.
Find the two natural numbers which differ by 5 and the sum of whose squares is 97.
Two natural numbers differ by 3. Find the numbers, if the sum of their reciprocals is `7/10`.
The denominator of a positive fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is 2.9; find the fraction.
Three positive numbers are in the ratio `1/2 : 1/3 : 1/4`. Find the numbers if the sum of their squares is 244.
Divide 20 into two parts such that three times the square of one part exceeds the other part by 10.
Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the squares of the other two by 60. Assume the middle number to be x and form a quadratic equation satisfying the above statement. Hence; find the three numbers.
Out of three consecutive positive integers, the middle number is p. If three times the square of the largest is greater than the sum of the squares of the other two numbers by 67; calculate the value of p.
The sum of two natural numbers is 5 and the sum of their reciprocals is `5/6`, the numbers are ______.
In a school, a class has 40 students out of which x are girls. If the product of the number of girls and number of boys in the class is 375; the number of boys in the class is ______.
