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प्रश्न
The table given below shows the weekly expenditures on food of some households in a locality
| Weekly expenditure (in Rs) | Number of house holds |
| 100 – 200 | 5 |
| 200- 300 | 6 |
| 300 – 400 | 11 |
| 400 – 500 | 13 |
| 500 – 600 | 5 |
| 600 – 700 | 4 |
| 700 – 800 | 3 |
| 800 – 900 | 2 |
Draw a ‘less than type ogive’ and a ‘more than type ogive’ for this distribution.
उत्तर
The frequency distribution table of less than type is as follows:
| Weekly expenditure (in Rs) (upper class limits) | Cumulative frequency (cf) |
| Less than 200 | 5 |
| Less than 300 | 5 + 6 = 11 |
| Less than 400 | 11 + 11 = 22 |
| Less than 500 | 22 + 13 = 35 |
| Less than 600 | 35 + 5 = 40 |
| Less than 700 | 40 + 4 = 44 |
| Less than 800 | 44 + 3 = 47 |
| Less than 900 | 47 + 2 = 49 |
Taking the lower class limits on x-axis and their respective cumulative frequencies on y-axis, its ogive can be obtained as follows
Now,
The frequency distribution table of more than type is as follows:
| Weekly expenditure (in Rs) (lower class limits) | Cumulative frequency (cf) |
| More than 100 | 44 + 5 = 49 |
| More than 200 | 38 + 6 = 44 |
| More than 300 | 27 + 11 = 38 |
| More than 400 | 14 + 13 = 27 |
| More than 500 | 9 + 5 = 14 |
| More than 600 | 5 + 4 = 9 |
| More than 700 | 2 + 3 = 5 |
| More than 800 | 2 |
Taking the lower class limits
on x-axis and their respective
cumulative frequencies on y-axis,
its ogive can be obtained as follows:
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संबंधित प्रश्न
The monthly profits (in Rs.) of 100 shops are distributed as follows:
| Profits per shop: | 0 - 50 | 50 - 100 | 100 - 150 | 150 - 200 | 200 - 250 | 250 - 300 |
| No. of shops: | 12 | 18 | 27 | 20 | 17 | 6 |
Draw the frequency polygon for it.
Find the median of the following data by making a ‘less than ogive’.
| Marks | 0 - 10 | 10-20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 | 80-90 | 90-100 |
| Number of Students | 5 | 3 | 4 | 3 | 3 | 4 | 7 | 9 | 7 | 8 |
Write the median class of the following distribution:
| Class | 0 – 10 | 10 -20 | 20- 30 | 30- 40 | 40-50 | 50- 60 | 60- 70 |
| Frequency | 4 | 4 | 8 | 10 | 12 | 8 | 4 |
The following are the ages of 300 patients getting medical treatment in a hospital on a particular day:
| Age (in years) | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 | 60 -70 |
| Number of patients | 6 | 42 | 55 | 70 | 53 | 20 |
Form a ‘less than type’ cumulative frequency distribution.
The following table gives the life-time (in days) of 100 electric bulbs of a certain brand.
| Life-tine (in days) | Less than 50 |
Less than 100 |
Less than 150 |
Less than 200 |
Less than 250 |
Less than 300 |
| Number of Bulbs | 7 | 21 | 52 | 9 | 91 | 100 |
Write the median class for the following frequency distribution:
| Class-interval: | 0−10 | 10−20 | 20−30 | 30−40 | 40−50 | 50−60 | 60−70 | 70−80 |
| Frequency: | 5 | 8 | 7 | 12 | 28 | 20 | 10 | 10 |
Find the mode of the following frequency distribution.
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
| Frequency | 8 | 10 | 10 | 16 | 12 | 6 | 7 |
Consider the following distribution:
| Marks obtained | Number of students |
| More than or equal to 0 | 63 |
| More than or equal to 10 | 58 |
| More than or equal to 20 | 55 |
| More than or equal to 30 | 51 |
| More than or equal to 40 | 48 |
| More than or equal to 50 | 42 |
The frequency of the class 30 – 40 is:
Form the frequency distribution table from the following data:
| Marks (out of 90) | Number of candidates |
| More than or equal to 80 | 4 |
| More than or equal to 70 | 6 |
| More than or equal to 60 | 11 |
| More than or equal to 50 | 17 |
| More than or equal to 40 | 23 |
| More than or equal to 30 | 27 |
| More than or equal to 20 | 30 |
| More than or equal to 10 | 32 |
| More than or equal to 0 | 34 |
The following are the ages of 300 patients getting medical treatment in a hospital on a particular day:
| Age (in years) | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 | 60 – 70 |
| Number of patients | 60 | 42 | 55 | 70 | 53 | 20 |
Form: More than type cumulative frequency distribution.
