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The time T, taken for a complete oscillation of a single pendulum with length l, is given by the equation T = 2πlg where g is a constant. Find the approximate percentage error in - Mathematics

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प्रश्न

The time T, taken for a complete oscillation of a single pendulum with length l, is given by the equation T = `2pi sqrt(l/g)` where g is a constant. Find the approximate percentage error in the calculated value of T corresponding to an error of 2 percent in the value of l

बेरीज

उत्तर

Given T = `2pi sqrt(l/g)`

On taking log both sides, we get

log T = `log 2 + log pi + 1/2 log "l" - 1/2 log "g"`

On differentiating both sides w. r. to l, we get

`1/"T" "dT"/"dl" = 1/21`

`1/"T" "dT"/"dl" Deltal = 1/(2l) Deltal`  ......(Multiplying both sides `Deltal`)

∴ `Delta"T" = "dT"/"dl" Deltal`

`1/"T" Delta"T" = 1/(2l) Deltal`

`(Delta"T")/"T" xx 100 = 1/2 (Deltal)/l xx 100`

= `1/2 xx 2`

= 1%

So, the percentage error in T is 1%

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Linear Approximation and Differentials
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Differentials and Partial Derivatives - Exercise 8.1 [पृष्ठ ६४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 8 Differentials and Partial Derivatives
Exercise 8.1 | Q 6 | पृष्ठ ६४

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