मराठी

The volume of the frustum of a cone is 13πh[r12+r22-r1r2], where h is vertical height of the frustum and r1, r2 are the radii of the ends. - Mathematics

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प्रश्न

The volume of the frustum of a cone is `1/3 pih[r_1^2 + r_2^2 - r_1r_2]`, where h is vertical height of the frustum and r1, r2 are the radii of the ends.

पर्याय

  • True

  • False

MCQ
चूक किंवा बरोबर

उत्तर

This statement is False.

Explanation:

Since, the volume of the frustum of a cone is `1/3 pi"h"["r"_1^2 + "r"_2^2 + "r"_1"r"_2]`, where h is vertical height of the frustum and r1, r2 are the radii of the ends.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Surface Areas and Volumes - Exercise 12.2 [पृष्ठ १४२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
पाठ 12 Surface Areas and Volumes
Exercise 12.2 | Q 5 | पृष्ठ १४२

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

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