हिंदी

The volume of the frustum of a cone is 13πh[r12+r22-r1r2], where h is vertical height of the frustum and r1, r2 are the radii of the ends. - Mathematics

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प्रश्न

The volume of the frustum of a cone is `1/3 pih[r_1^2 + r_2^2 - r_1r_2]`, where h is vertical height of the frustum and r1, r2 are the radii of the ends.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य

उत्तर

This statement is False.

Explanation:

Since, the volume of the frustum of a cone is `1/3 pi"h"["r"_1^2 + "r"_2^2 + "r"_1"r"_2]`, where h is vertical height of the frustum and r1, r2 are the radii of the ends.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Surface Areas and Volumes - Exercise 12.2 [पृष्ठ १४२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 12 Surface Areas and Volumes
Exercise 12.2 | Q 5 | पृष्ठ १४२

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