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Question
The volume of the frustum of a cone is `1/3 pih[r_1^2 + r_2^2 - r_1r_2]`, where h is vertical height of the frustum and r1, r2 are the radii of the ends.
Options
True
False
Solution
This statement is False.
Explanation:
Since, the volume of the frustum of a cone is `1/3 pi"h"["r"_1^2 + "r"_2^2 + "r"_1"r"_2]`, where h is vertical height of the frustum and r1, r2 are the radii of the ends.
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