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Using interpolation estimate the business done in 1985 from the following data Year 1982 1983 1984 1986 Business done(in lakhs) 150 235 365 525 - Business Mathematics and Statistics

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प्रश्न

Using interpolation estimate the business done in 1985 from the following data

Year 1982 1983 1984 1986
Business done
(in lakhs)
150 235 365 525
बेरीज

उत्तर

Here the intervals are unequal.

By Lagrange’s formula we have,

x0 = 1982

x1 = 1983

x2 = 1984

x3 = 1986

y0 = 150

y1 = 235

y2 = 365

y3 = 525 and x = 1985.

y = `"f"(x) = ((x - x_1)(x - x_2)(x - x_3))/((x_0 - x_1)(x_0 - x_2)(x_0 - x_3)) xx y_0 + ((x - x_0)(x - x_2)(x - x_3))/((x_1 - x_0)(x_1 - x_2)(x_1 - x_3)) xx y_1 + ((x - x_0)(x - x_1)(x - x_3))/((x _2 - x_0)(x_2 - x_1)(x_2 - x_3)) xx y_2 + ((x - x_0)(x - x_1)(x - x_2))/((x_3 - x_0)(x_3 - x_1)(x_3 - x_2)) xx y_3`

y = `((1985 - 1983)(1985 - 1984)(1985 - 1986))/((1982 - 1983)(1982 - 1984)(1982 - 1986)) xx 150 + ((1985 - 1982)(1985 - 1984)(1985 - 1986))/((1983 - 1982)(1983 - 1984)(1983 - 1986)) xx 235  ((198  - 982)(1985 - 1983)(985 - 1986))/((984 - 1982)(1984 - 1983)(1984 - 1986)) xx 365 + ((1985 - 1982)(1985 - 1983)(1985 - 1984))/((1986 - 1982)(1986 - 1983)(1986 - 1984)) xx 525`

= `((2)(1)(-1))/((-1)(-2)(-4)) xx 150 + ((3)(1)(-1))/((1)(-1)(-3)) xx 235 + ((3)(2)(-1))/((2)(1)(-)) xx 365  + ((3)(2)(1))/((4)(3)(2)) xx 525`

= `(-2 xx 150)/(-8) + (-3 xx 235)/3 + (-6 xx 365)/(-4) xx (6 xx 525)/24`

= 37.5 – 235 + 547.5 + 131.25

= 716.125 – 235

= 481.25

∴ Business done in the year 1985 is 481.25 lakhs.

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Interpolation
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पाठ 5: Numerical Methods - Exercise 5.2 [पृष्ठ १२०]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
पाठ 5 Numerical Methods
Exercise 5.2 | Q 11 | पृष्ठ १२०
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