Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
उत्तर
(4 – mn)(mn + 4)
(4 – mn)(mn + 4) can be written as (4 – mn) (4 + mn = (4 + mn)(4 – mn)
Substituting a = 4 and b = mn
In (a + b)(a – b) = a2 – b2, we get
(4 + mn)(4 – mn) = 42 – (mn)2
= 16 – m2 n2
APPEARS IN
संबंधित प्रश्न
Factorise the following expressions
m2 + m – 72
Find the value of (x – y)(x + y)(x2 + y2)
The value of p for 512 – 492 = 100p is 2.
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Using suitable identities, evaluate the following.
(132)2 – (68)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
a4 – (a – b)4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – (3y + z)2
Find the value of a, if pqa = (3p + q)2 – (3p – q)2
Find the value of `(6.25 xx 6.25 - 1.75 xx 1.75)/(4.5)`