Question

Voltage applied between cathode and anode of an X-ray tube is 18 kV. Calculate the minimum wavelength of the X-rays produced.

Answer 1

Here, V = 18 k, V = 18000V

We know, 
λ_min = ${\displaystyle \frac{hc}{eV}}$
= ${\displaystyle \frac{6.6\times {10}^{-34} \times 3\times {10}^8}{1.6\times {10}^{-19}\times 18000}}$

= ${\displaystyle \frac{6.6\times 3}{1.6\times 18}\times {10}^{-10}}$

= 0.688 x 10^-10 

= 6.88 x 10^-11 m