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Question
Voltage applied between cathode and anode of an X-ray tube is 18 kV. Calculate the minimum wavelength of the X-rays produced.
Solution
Here, V = 18 k, V = 18000V
We know,
λmin = `(hc)/(eV)`
= `( 6.6 xx 10^-34 xx 3 xx 10^8 )/( 1.6 xx 10^-19 xx 18000 )`
= `( 6.6 xx 3 )/( 1.6 xx 18 ) xx 10^-10`
= 0.688 x 10-10
= 6.88 x 10-11 m
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