मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

What is the (a) momentum, (b) speed, and (c) de Broglie wavelength of an electron with kinetic energy of 120 eV. - Physics

Advertisements
Advertisements

प्रश्न

What is the

(a) momentum,

(b) speed, and

(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.

संख्यात्मक

उत्तर

Kinetic energy of the electron, Ek = 120 eV

Planck’s constant, h = 6.6 × 10−34 Js

Mass of an electron, m = 9.1 × 10−31 kg

Charge on an electron, e = 1.6 × 10−19 C

(a) For the electron, we can write the relation for kinetic energy as:

`"E"_"k" = 1/2"mv"^2`

Where,

v = Speed of the electron

∴ `"v"^2 = sqrt((2"eE"_"k")/"m")`

= `sqrt((2 xx 1.6 xx 10^(-19) xx 120)/(9.1 xx 10^(-31)))`

= `sqrt(42.198 xx 10^12)`

= 6.496 × 106 m/s

Momentum of the electron, p = mv

= 9.1 × 10−31 × 6.496 × 106

= 5.91 × 10−24 kg m s−1

Therefore, the momentum of the electron is 5.91 × 10−24 kg m s−1.

(b) Speed of the electron, v = 6.496 × 106 m/s

(c) De Broglie wavelength of an electron having a momentum p, is given as:

`lambda = "h"/"p"`

= `(6.6 xx 10^(-34))/(5.91 xx 10^(-24))`

= 1.116 × 10−10 m

= 0.112 nm

Therefore, the de Broglie wavelength of the electron is 0.112 nm.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Dual Nature of Radiation and Matter - Exercise [पृष्ठ ४०८]

APPEARS IN

एनसीईआरटी Physics [English] Class 12
पाठ 11 Dual Nature of Radiation and Matter
Exercise | Q 11.13 | पृष्ठ ४०८
एनसीईआरटी Physics [English] Class 12
पाठ 11 Dual Nature of Radiation and Matter
Exercise | Q 13 | पृष्ठ ४०८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

A proton and an α-particle have the same de-Broglie wavelength Determine the ratio of  their speeds.


The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which

(a) an electron, and

(b) a neutron, would have the same de Broglie wavelength.


For what kinetic energy of a neutron will the associated de Broglie wavelength be 1.40 × 10−10 m?


What is the de Broglie wavelength of a nitrogen molecule in air at 300 K? Assume that the molecule is moving with the root-mean square speed of molecules at this temperature. (Atomic mass of nitrogen = 14.0076 u)


Obtain the de Broglie wavelength of a neutron of kinetic energy 150 eV. As you have an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. (mn= 1.675 × 10−27 kg)


Obtain the de Broglie wavelength associated with thermal neutrons at room temperature (27°C). Hence explain why a fast neutron beam needs to be thermalised with the environment before it can be used for neutron diffraction experiments.


Compute the typical de Broglie wavelength of an electron in a metal at 27°C and compare it with the mean separation between two electrons in a metal which is given to be about 2 × 10−10 m.


The energy and momentum of an electron are related to the frequency and wavelength of the associated matter wave by the relations:

E = hv, p = `"h"/lambda`

But while the value of λ is physically significant, the value of v (and therefore, the value of the phase speed vλ) has no physical significance. Why?


State any one phenomenon in which moving particles exhibit wave nature.


Why photoelectric effect cannot be explained on the basis of wave nature of light? Give reasons.


 Show with the help of a labelled graph how their wavelength (λ) varies with their linear momentum (p).


The wavelength of the matter wave is dependent on ______.


The de-Broglie wavelength associated with a material particle when it is accelerated through a potential difference of 150 volt is 1 Å. What will be the de-broglie wavelength associated with the same particle when it is accelerated through a potential difference of 4500 V?


A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to ______.


Two particles A1 sand A2 of masses m1, m2 (m1 > m2) have the same de Broglie wavelength. Then ______.

  1. their momenta are the same.
  2. their energies are the same.
  3. energy of A1 is less than the energy of A2.
  4. energy of A1 is more than the energy of A2.

An electron is accelerated from rest through a potential difference of 100 V. Find:

  1. the wavelength associated with
  2. the momentum and
  3. the velocity required by the electron.

The equation λ = `1.227/"x"` nm can be used to find the de Brogli wavelength of an electron. In this equation x stands for:

Where,

m = mass of electron

P = momentum of electron

K = Kinetic energy of electron

V = Accelerating potential in volts for electron


For which of the following particles will it be most difficult to experimentally verify the de-Broglie relationship?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×