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प्रश्न
When a brown compound of manganese (A) is treated with \[\ce{HCl}\] it gives a gas (B). The gas taken in excess, reacts with \[\ce{NH3}\] to give an explosive compound (C). Identify compounds A, B and C.
उत्तर
The compounds A, B and C are as follows:
A = \[\ce{MnO2}\], B = \[\ce{Cl2}\], C = \[\ce{NCl3}\]
The reactions are explained as under:
\[\ce{\underset{(A)}{MnO2} + 4HCl -> MnCl2 + \underset{(B)}{Cl2} + 2H2O}\]
\[\ce{\underset{(Excess)}{3Cl2} + NH3 -> \underset{(C)}{NCl3} + 3HCl}\]
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संबंधित प्रश्न
To what extent do the electronic configurations decide the stability of oxidation states in the first series of the transition elements? Illustrate your answer with examples.
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(i) \[\ce{Cr}\]
(ii) \[\ce{Co}\]
(iii) \[\ce{Cu}\]
(iv) \[\ce{Ni}\]
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Column I (Property) | Column II (Metal) | |
(i) | An element which can show +8 oxidation state | (a) \[\ce{Mn}\] |
(ii) | 3d block element that can show | (b) \[\ce{Cr}\] |
upto +7 oxidation state | (c) \[\ce{Os}\] | |
(iii) | 3d block element with highest melting point | (d) \[\ce{Fe}\] |
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