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Question
When a brown compound of manganese (A) is treated with \[\ce{HCl}\] it gives a gas (B). The gas taken in excess, reacts with \[\ce{NH3}\] to give an explosive compound (C). Identify compounds A, B and C.
Solution
The compounds A, B and C are as follows:
A = \[\ce{MnO2}\], B = \[\ce{Cl2}\], C = \[\ce{NCl3}\]
The reactions are explained as under:
\[\ce{\underset{(A)}{MnO2} + 4HCl -> MnCl2 + \underset{(B)}{Cl2} + 2H2O}\]
\[\ce{\underset{(Excess)}{3Cl2} + NH3 -> \underset{(C)}{NCl3} + 3HCl}\]
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