Advertisements
Advertisements
प्रश्न
Which of the following are the roots of `3x^2+2x-1=0`
`-1/2`
उत्तर
On subtracting x=`(-1/2)` in the given equation, we get
L.H.S=`3x^2+2x-1`
=`3xx(-1/2)^2+2xx(-1/2)-1`
`=3xx1/4-1-1`
`=3/4-2`
`-(3-8)/4`
=-5/4≠ 0
Thus, L.H.S R.H.S.
Hence, (-1/2) is a solution of` (3x^2+2x-1=0)`
APPEARS IN
संबंधित प्रश्न
Write the discriminant of the following quadratic equations:
x2 - 2x + k = 0, k ∈ R
` 2x^2-7x+6=0`
`(x-1)(2x-1)=0`
`2x^2+5sqrt3x+6=0`
`3x^2-2x+2=0.b`
`36x^2-12ax+(a^2-b^2)=0`
`x^2+5x-(a^+a-6)=0`
For what values of k are the roots of the quadratic equation `3x^2+2kx+27` real and equal ?
Find the values of p for which the quadratic equation `(p+1)x^2-6(p+1)x+3(p+9)=0` `p≠-11`has equal roots. Hence find the roots of the equation.
Find the values of k for which the given quadratic equation has real and distinct roots:
`9x^2+3kx+4=0`
