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Question
Which of the following are the roots of `3x^2+2x-1=0`
`-1/2`
Solution
On subtracting x=`(-1/2)` in the given equation, we get
L.H.S=`3x^2+2x-1`
=`3xx(-1/2)^2+2xx(-1/2)-1`
`=3xx1/4-1-1`
`=3/4-2`
`-(3-8)/4`
=-5/4≠ 0
Thus, L.H.S R.H.S.
Hence, (-1/2) is a solution of` (3x^2+2x-1=0)`
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