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Question
Find the value of k for which x = 1is a root of the equation `x^2+kx+3=0`
Solution
It is given that (x=1) is a root of `(x^2+kx+3=0)`
Therefore, (x=1) must satisfy the equation.
`⇒ (1)^2+kxx1+3=0`
`⇒k+4=0`
`⇒k=-4`
Hence, the required value of k is -4.
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