Advertisements
Advertisements
प्रश्न
Find the value of k for which x = 1is a root of the equation `x^2+kx+3=0`
उत्तर
It is given that (x=1) is a root of `(x^2+kx+3=0)`
Therefore, (x=1) must satisfy the equation.
`⇒ (1)^2+kxx1+3=0`
`⇒k+4=0`
`⇒k=-4`
Hence, the required value of k is -4.
APPEARS IN
संबंधित प्रश्न
Write the discriminant of the following quadratic equations:
x2 - x + 1 = 0
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
16x2 = 24x + 1
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
x2 + x + 2 = 0
Find the value of a and b for which `x=3/4`and `x =-2` are the roots of the equation `ax^2+bx-6=0`
`x^2-6x+4=0`
`x^2-(sqrt3+1)x+sqrt3=0`
`x+1/x=3,x≠0`
`x^2-(2b-1)x+(b^2-b-20)=0`
If the roots of the equation `(a^2+b^2)x^2-2(ac+bd)x+(c^2+d^2)=0`are equal, prove that `a/b=c/d`
Solve for x: \[\frac{16}{x} - 1 = \frac{15}{x + 1}, x \neq 0, - 1\]
