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प्रश्न
Which of the following are the roots of `3x^2+2x-1=0?`
`1/3`
उत्तर
On subtracting `x= 1/3` in the given equation , We get :
L.H.S = `3x^2x-1`
`=3xx(1/3)^2+2xx1/3-1`
=`3xx1/9+2/3-1`
`=(1+2-3)/3`
`=0/3`
=0
R.H.S
Thus, `(1/3)`is a root of `(3x^2+2x-1=0)`
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