Advertisements
Advertisements
प्रश्न
Why is the potential inside a hollow spherical charged conductor constant and has the same value of as on its surface?
उत्तर
Electric field inside the shell is zero. So no work is done in moving a charge inside the shell. This implies that potential is constant, and therefore equal to its value at the surface i.e.
`V=1/(4piE_0) q/r`
APPEARS IN
संबंधित प्रश्न
A charge Q is uniformly distributed over a large plastic plate. The electric field at a point P close to the centre of the plate is 10 V m−1. If the plastic plate is replaced by a copper plate of the same geometrical dimensions and carrying the same charge Q, the electric field at the point P will become
In the following figure shows a charge q placed at the centre of a hemisphere. A second charge Q is placed at one of the positions A, B, C and D. In which position(s) of this second charge, the flux of the electric field through the hemisphere remains unchanged?
(a) A
(b) B
(c) C
(d) D
A charge Q is uniformly distributed over a rod of length l. Consider a hypothetical cube of edge l with the centre of the cube at one end of the rod. Find the minimum possible flux of the electric field through the entire surface of the cube.
The electric field in a region is given by
`vec"E"= 3/5"E"_0 vec"i" + 4/5 "E"_0 vec "i" "with" " E"_0 = 2.0 xx 10^3 "N""C"^-1.`
Find the flux of this field through a rectangular surface of area 0⋅2 m2 parallel to the y-z plane.
A charged particle with a charge of −2⋅0 × 10−6 C is placed close to a non-conducting plate with a surface charge density of 4.0 × 10-6Cm0-2. Find the force of attraction between the particle and the plate.
Three identical metal plates with large surface areas are kept parallel to each other as shown in the following figure. The leftmost plate is given a charge Q, the rightmost a charge −2Q and the middle one is kept neutral. Find the charge appearing on the outer surface of the rightmost plate.
A uniform electric field of 10 N C−1 exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50 cm.
Some equipotential surface is shown in the figure. What can you say about the magnitude and the direction of the electric field?
Answer the following question.
Prove that the average energy density of the oscillating electric field is equal to that of the oscillating magnetic field.
Two charged conducting spheres of radii a and b are connected to each other by a wire. Find the ratio of the electric fields at their surfaces.
