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Write condensed orbital notation of electronic configuration of the following element: Silicon (Z = 14) - Chemistry

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प्रश्न

Write condensed orbital notation of electronic configuration of the following element:

Silicon (Z = 14)

एका वाक्यात उत्तर

उत्तर

Element Condensed orbital notation
Silicon (Z = 14) [Ne] 3s2 3p2
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पाठ 4: Structure of Atom - Exercises [पृष्ठ ५४]

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बालभारती Chemistry [English] 11 Standard
पाठ 4 Structure of Atom
Exercises | Q 6. (L)(d) | पृष्ठ ५४

संबंधित प्रश्‍न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 3; l =1.


Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


Choose the correct option.

Principal Quantum number describes -


Define the term Electronic configuration


State the order of filling atomic orbitals following Aufbau principle.


Explain the anomalous behaviour of copper.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 2, l = 1


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 4, l = 2


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 3, l = 2


Write electronic configurations of \[\ce{Fe, Fe2+, Fe3+}\].


Write a note on ‘Principal Quantum number.


The principal quantum number (n) and magnetic quantum number (ml) for the valence electrons of rubidium atom (Z = 37) are ____________ respectively.


Which one of the following is NOT possible?


Which of the following options does not represent ground state electronic configuration of an atom?


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

Which of the following sets of quantum numbers are correct?

  `n` `l` `m_l`
(i) 1 1 +2
(ii) 2 1 +1
(iii) 3 2 –2
(iv) 3 4 –2

Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.


Which of the following orbitals are degenerate?

3dxy, 4dxy 3dz2, 3dyz, 4dyz, 4dz2  


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5p, 4d, 5d, 4f, 6s


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5f, 6d, 7s, 7p


Match the following species with their corresponding ground state electronic configuration.

Atom / Ion Electronic configuration
(i) \[\ce{Cu}\] (a) 1s2 2s2 2p6 3s2 3p6 3d10
(ii) \[\ce{Cu^{2+}}\] (b) 1s2 2s2 2p6 3s2 3p6 3d10 4s2
(iii) \[\ce{Zn^{2+}}\] (c) 1s2 2s2 2p6 3s2 3p6 3d10 4s1
(iv) \[\ce{Cr^{3+}}\] (d) 1s2 2s2 2p6 3s2 3p6 3d9
  (e) 1s2 2s2 2p6 3s2 3p6 3d3

Match the quantum numbers with the information provided by these.

Quantum number Information provided
(i) Principal quantum number (a) orientation of the orbital
(ii) Azimuthal quantum number (b) energy and size of orbital
(iii) Magnetic quantum number (c) spin of electron
(iv) Spin quantum number (d) shape of the orbital

Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2

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