Advertisements
Advertisements
प्रश्न
Write the formula of an oxo-anion of Manganese (Mn) in which it shows the oxidation state equal to its group number.
उत्तर
Formula of oxo-anion of manganese (Mn) in which it shows the oxidation state equal to its group number (7) is `Mn_4^(-)`
Mn + (-2 ×4) = -1
Mn - 8 = -1
Mn = +7
Oxidation of Mn in `MnO_4^(-)` is +7 which is equal to its group number 7.
संबंधित प्रश्न
Complete the following chemical equation
8MnO4- + 3S2O32- + H2O →
Indicate the steps in the preparation of K2Cr2O7 from chromite ore.
Complete the following equation :
Account for the following :
Manganese shows maximum number of oxidation states in 3d series.
Using IUPAC norms write the formulae of Potassium trioxalatochromate (III)
Generally transition elements and their salts are coloured due to the presence of unpaired electrons in metal ions. Which of the following compounds are coloured?
(i) \[\ce{KMnO4}\]
(ii) \[\ce{Ce(SO4)2}\]
(iii) \[\ce{TiCl}\]
(iv) \[\ce{Cu2 Cl2}\]
When \[\ce{Cu^2+}\] ion is treated with \[\ce{KI}\], a white precipitate is formed. Explain the reaction with the help of chemical equation.
KMnO4 is coloured due to ______.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.