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Question
10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be:
(a) 4 mL
(b) 8 mL
(c) 12 mL
(d) 16 mL
Solution
16 mL
It is given that 10 mL of a solution of NaOH is completely neutralised by 8 mL of a solution of HCl. Hence, 20 mL of the solution of NaOH, which is double the amount taken earlier, will require double the solution of HCl taken earlier, i.e., 16 mL, to be completely neutralised.
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