Advertisements
Advertisements
Question
200 g of hot water at 80°C is added to 400 g of cold water at 10°C. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water = 4200 J kg-1K-1.
Solution
Mass of hot water (m1) = 200g
Temperature of hot water (T1) = 80°C
Mass of cold water (m2) = 400g
Temperature of cold water (T2) =10°C
Final temperature (T) = ?
m1 c1 (T1 - T) = m2 c2 (T - T2)
c1 = c2
T = `("m"_1 "T"_1 + "m"_2 "T"_2)/("m"_2 + "m"_1)`
`T = (200 xx 80 + 400 xx 10)/600`
T = 33.3°C
APPEARS IN
RELATED QUESTIONS
What is a calorimeter?
A piece of iron of mass 2.0 kg has a heat capacity of 966 J K-1. Find heat energy needed to warm it by 15°C.
Explain the melting point ?
Find the result of mixing 10 g of ice at - 10℃ with 10 g of water at 10℃. Specific heat capacity of ice = 2.1 J kg-1 K-1, Specific latent heat of ice = 336 J g-1 and specific heat capacity of water = 4.2 J kg-1 K-1.
State the principle of calorimeter and define calorie and kilocalorie.
Some heat is given to 120 g of water and its temp. rises by 10 K. When the same amount of heat is given to 60 g of oil, its temp. rises by 40 K. The Sp. heat of water is 4200 J/kgK. Calculate:
(a) The amount of heat in joules given to water,
(b) The specific heat capacity of the oil.
40 g of ice at -16°C is dropped into water at 0°C, when 4 g of water freezes into ice. If specific heat capacity of ice is 2100 J/kg°C, what will be the latent heat of fusion of ice?
Name two factors on which the heat energy librated by a body on cooling depends.
Write one characteristic property of the material chosen for making a calorimeter.
