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Question
A = `[(1, 2),(-2, 3)]` and B = `[(-2, -1),(1, 2)], "C" [(0, 3),(2, -1)]`Find A + 2B – 3C
Solution
A = `[(1, 2),(-2, 3)]` and B = `[(-2, -1),(1, 2)], "C" [(0, 3),(2, -1)]`
∴ A + 2B – 3C
= `[(1, 2),(-2, 3)] + 2[(-2, -1),(1, 2)] -3[(0, 3),(2, -1)]`
= `[(1, 2),(-2, 3)] + [(-4, -2),(2, 4)] - [(0, 9),(6, -3)]`
= `[(1 - 4 - 0, 2 - 2 - 9),(-2 + 2 - 6, 3 + 4 + 3)]`
= `[(-3, -9),(-6, 10)]`.
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