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Question
Given `A = [(1, 1),(-2, 0)]` and `B = [(2, -1), (1, 1)]`. Solve for matrix X:
3X + B + 2A = 0
Solution
3X + B + 2A = 0
3X = – B – 2A
X = `(-1)/3(B + 2A)`
= `(-1)/3B - 2/3A`
= `(-1)/3[(2, -1),(1, 1)] - 2/3[(1, 1),(-2, 0)]`
= `[((-2)/3, 1/3),((-1)/3, (-1)/3)] - [(2/3, 2/3),((-4)/3, 0)]`
= `[(-2/3 - 2/3, 1/3 - 2/3),(-1/3 - (-4/3), -1/3 - 0)]`
= `[((-4)/3, (-1)/3),((-1)/3 + 4/3, (-1)/3)]`
= `[((-4)/3, (-1)/3),(3/3, (-1)/3)]`
= `[((-4)/3, (-1)/3),(1, (-1)/3)]`
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