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Question
Given `A = [(2, 1),(3, 0)], B = [(1, 1),(5, 2)]` and `C = [(-3, -1),(0, 0)]`; find A + 2C – B
Solution
A + 2C – B
= `[(2, 1),(3, 0)] + 2[(-3, -1),(0, 0)] + [(1, 1),(5, 2)]`
= `[(2, 1),(3, 0)] + [(-6, -2),(0, 0)] - [(1, 1),(5, 2)]`
= `[(2 - 6 - 1, 1- 2 - 1),(3 + 0 - 5, 0 + 0 - 2)]`
= `[(2 - 7, 1 - 3),(3 - 5, 0 - 2)]`
= `[(-5, -2),(-2, -2)]` or `-[(5, 2),(2, 2)]`
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