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Question
If `[(4, -2),(4, 0)] + 3A = [(-2, -2),(1, -3)]`; find A.
Solution
`[(4, -2),(4, 0)] + 3A = [(-2, -2),(1, -3)]`
`3A = [(-2, -2),(1, -3)] - [(4, -2),(4, 0)]`
`3A = [(-2-4, -2 + 2),(1 - 4, -3- 0)]`
`3A = [(-6, 0),(-3, -3)]`
`A = 1/3[(-6, 0),(-3, -3)]`
= `[(-2, 0),(-1, -1)]`
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