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Question
Given A = `[(-3, 6),(0, -9)]` and At is its transpose matrix. Find `1/2 A - 1/3 A^t`
Solution
A = `[(-3, 6),(0, -9)]`
At = `[(-3, 0),(6, -9)]`
`1/2 A - 1/3 A^t = 1/2[(-3, 6),(0, -9)] - 1/3[(-3, 0),(6, -9)]`
= `[((-3)/2, 3),(0, (-9)/2)] - [(-1, 0),(2, -3)]`
= `[(-3/2 - (-1), 3 - 0),(0 - 2, -9/2 - (-3))]`
= `[(-3/2 + 1, 3),(-2, -9/2 + 3)]`
= `[((-1)/2, 3),(-2, (-3)/2)]`
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